replace ';' LIST ';' REGEX (';' STRING (';' STRING)? )?
Macro
Replace elements in a list when it matches a regular expression
replace ; <list> ; <regex> [ ; <replacement> [ ; <delimiter> ] ]
Replace all parts within elements of the list that match the regular expression regex with the replacement. The replace macro uses a simple splitter, the regular expression \s*,\s*, to split the list into elements. So any comma in the input list will be use to split the list into elements. See replacelist for an equivalent macro which has a more sophisticated splitter which takes quoted sections of the string into account.
The replacement can use the $[0-9] back references defined in the regular expressions. The macro uses element.replaceAll(regex,replacement) method to do the replacement. The default replacement is the empty string. The default delimiter is “,”.
Examples
impls: foo,bar
${replace;${impls};$;.jar} => foo.jar,bar.jar